(i) To calculate the energy of a photon in joules, we can use the formula:
E = hf
Where E is the energy of the photon, h is Planck’s constant, and f is the frequency of the photon.
Given:
Frequency (f) = 5.02 x 10^14 Hz
Planck’s constant (h) = 6.6 x 10^-34 Js
Substituting these values into the formula, we get:
E = (6.6 x 10^-34 Js) * (5.02 x 10^14 Hz)
E = 3.3132 x 10^-19 J
Therefore, the energy of the photon in joules is approximately 3.3132 x 10^-19 J.
(ii) To calculate the energy of a photon in electron volts (eV), we can use the conversion factor:
1 eV = 1.6 x 10^-19 J
Given that we already calculated the energy of the photon as approximately 3.3132 x 10^-19 J, we can convert this to electron volts by dividing it by the conversion factor:
E(eV) = (3.3132 x 10^-19 J) / (1.6 x 10^-19 J/eV)
E(eV) ≈ 2.07075 eV
Therefore, the energy of the photon in electron volts is approximately 2.07075 eV.
